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Reaction engineering · Lesson 5 of 7

Reactors in series

A CSTR is big because it drops straight to the final concentration. Split the job into several smaller tanks in a row and only the last one runs that low; the first ones work at higher concentration, faster. The total volume shrinks.

For first-order reactions in N equal CSTRs, each multiplies the remaining A by 1 ÷ (1 + kτ_each), so 1 − X = 1 ÷ (1 + kτ_each)ᴺ. To reach 90% with two tanks: (1 + kτ)² = 10, so kτ = √10 − 1 = 2.16, and with k = 0.1 per minute each tank needs τ = 21.6 minutes, 43.2 in total. One CSTR needed 90 minutes and a PFR 23.

As N grows, a chain of tanks behaves more and more like a plug flow reactor: with infinitely many, it is one. Even three or four tanks get most of the benefit. That's why big continuous fermenters and polymerization lines often use a short train of stirred tanks.

Order matters when reactors differ. For the usual positive-order reactions you want high concentration where the reaction is happening, so you'd put a PFR before a CSTR rather than after, if you had to have both. For conversion targets near 100%, a CSTR followed by a small PFR "polishing" step is common.

Choosing a reactor comes down to the reaction and the job: phases involved, how much heat it gives, the conversion and selectivity wanted, scale, cost and safety. The rest of the course covers heat and selectivity.

Practice

Each of two equal CSTRs in series has kτ = 1. What's the overall conversion of a first-order reaction? Give a decimal.

More info

Quick reference

N CSTRs, first order1 − X = 1 ÷ (1 + kτ)ᴺ
Many tanksApproach plug flow.
Positive orderPFR before CSTR.
PolishingSmall PFR after a CSTR for the last bit.

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